AutoCAD Inventor :: Show Angular Dimension In Dual Units?
Sep 9, 2012is there any way I can place dimension on drawing that would be in dual units (in decimal degrees and in deg min sec)?
I did not find this possible so far.
is there any way I can place dimension on drawing that would be in dual units (in decimal degrees and in deg min sec)?
I did not find this possible so far.
How do i get the leading zero to show on an angular dimension for the seconds? as in: 108d 36' 03" ?
View 1 Replies View RelatedI have a block of a guide sign with directions and azimuth angles. I made arrows rotatable and angles were changing ok. But when I try to rotate an arrow into zero position, dimension shows 180. I need the dimension to show 0 degree. How can I do it?
And I can’t make angular dimension show degrees greater than 180 even if I specify vertex – after rotation angle shifts on the other side. I gave up and used back azimuth.
And I can't make an attachment: "The contents of the attachment doesn't match its file type"?
I am trying to put an angular dimension from a hole to a slot positioned planes 90degrees to each other. How can I achieve this? Typically, it depends on how it is put into the ipt file but I didn't know how else to put the slot in therefore only a point was put in at that angle.
View 2 Replies View RelatedI don't know if it's a bug...
When using dual units on a drawing ( millimeters and inches for example) the symbol "diameter" is no reproduce in the second unit ... see pictures below!
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Autodesk Product Design Suite Ultimate 2013
Win 7 Pro 64 bits SP1
Bi-Xeon E5520 (2x Quad-core @2.27GHz)
Quadro Fx 1800 768Mo GDDR3
6Go Ram DDR3 667MHz ECC
Any way to show dual dimensions as shown on the right rather than the one which we get on the left
Config :: Intel (R) Xeon (R) CPU E31245 @ 3.30 GHz, 16.0 GB, 64bit win7
Inventor 2013 and Vault Basic 2013
I cannot figure out how to dual dimension a bend like so:
DIRECTION DEGREES RIMPERIAL [RMETRIC]
e.g. DOWN 90 R1/2"[13] preferred
or DOWN 90 R1/2"[R13] okay
There should be a degree symbol after the 90 in my examples but I can't figure out how to type it here. I can get DOWN 90 R1/2"[DOWN 90 R13] but it's too long.
why after selecting Dimension, Angular, then selecting two lines, I do not get the angle between them? I am using v 2000 if it matters. I enclose a screen shot of the two lines I need the angle of.
View 9 Replies View RelatedUnable to find a way to show dual dimensions in my model shetch.
View 8 Replies View RelatedWhy does my angular dimension have a straight dimension line instead of curved?
View 4 Replies View RelatedIs there any way possible to have an angular dimension to denote an angle of greater than 180 degrees?
View 4 Replies View RelatedI am displaying dual units in a drawing with primary units being Customary. The metric unit displayed is incorrect.
View 1 Replies View RelatedThe only formats I see for angular dimensions in the toolbox are degrees, °, radians, gradians. Is there any way set angular units be deg-min-sec (° ' ") format?
View 2 Replies View RelatedCannot find a way to set up angular dimensions to show that first zero if the minutes or seconds value is less than ten.
Desired: <degrees>08'05"
Stuck with: <degrees>8'5"
I would like to show such a dimension, like S1 in attachment. It is really value of tolerance of nominal 0 dimension.
View 2 Replies View RelatedI want to be able to use the same dimension parameter as a previous component pattern to create a new component pattern. Is there a way to be able to do this? On features, you can use the Show Dimension and then select the dimension you want. With rectangular patterns I don't see a way to do this and there is no way to even note which parameter it gave it as it is being created. I guess I could name the parameter on the fly and then use that same name, but was wondering if there was a different way.
View 2 Replies View RelatedThis is the first I've noticed this, but a sketch in an assembly does not allow to show the dimensions as an expression? In a .ipt sketch you can right click and the pop-up menu has an option to show the dimensions in different forms. I do not get this in an assembly sketch.
I do not know if this is me or not. It's just curious that it does not do that.
If I type the command UNITS and change the insertion scale to millimeter (mine was inches), what is going to happen? At first i used inches to draw 5 inches line and the get the dimension of it, second i drew again a line using the millimeter in units, but when i measured it still it is exact to the first line that i draw.
View 9 Replies View RelatedWe are having an issue with Dimensioning and the Primary Units not maintaining the correct value. We use metric so the multiplier of 25.4 or .039370079 for Dim Scale Linear would be used in our Dimension Styles depending on if we are drawing in model space or annotating in paper space. We have created specific Dim Styles for Model and Paper space. Every so often some of us will us the Dim Style for paper space and a metric unit would be shown. When we go into the properties of that dimension and change the Dim Scale Linear to 1 it shows as a different dimension then it actually is. After looking at the correct dimenion, we noticed the Dim Scale Linear shows .9449 but gives the correct dimension.
Note: We are drawing in Metric a multiplier of 25.4, our dimensions are done in english. A scale factor of .039370079 is used to accomplish this.
There is a simple fix with Match Properties but it still doesn't answer why our dimension show up wrong with a different multiplier for Dim Scale Linear.
I'm having an issue with dimensions changing from when I save the drawing to when I reopen it.
I'm using AutoCAD Mechanical 2009, exclusively in 2D. I save drawings in AutoCAD 2000/LT 2000 Drawing format to maintain backwards compatibility with our legacy documents which are still in regular use.
The exact process is:
1. Create dimension in existing drawing.
2. Set units of dimension. Typically this is fractional.
3. Save and close drawing.
4. Reopen drawing, and all of the dimensions units are set to decimal to the fourth decimal point.
If I interact with the dimension in any way, it will return to its set unit. For example, if I double click on it to bring up the Power Dimensioning window and just click Okay without altering anything, it will change back to its set unit. Likewise, if I move the dimension itself it will return to its set unit as well.
So far my solution has been to simply select the entire drawing at once, then move it X units one way, then X units back. The move back and forth will return all the dimensions to their set units.
Obviously this is not ideal, especially when sending drawings to co-workers who are unaware of the issue or even using different versions of AutoCAD.
I have a drawing from a contractor that is dimensioned in metric units. I have been tasked with converting the displayed units to inches for our machine shop. I have tried to display alternate units but they don't appear, yes, I did check the "display alternate units" box. I am using AutoCAD 2013.
View 9 Replies View RelatedIs it possible to obtain Architectural unit dimensioning (ft and inches) in a metric drawing ?
View 3 Replies View RelatedI just started using Autocad LT 2004. It seem unusual that when a dimension is drawn there is no reference to the unit such as inch or feet?
View 3 Replies View RelatedIs it possible to have text below the angular dimension line like you can with most other dimensions. The attached pic shows my 10 dimension with the type. Under the line and my 30 dimension with type. Under the line but the type. Under the 30 is just a text box I eye-balled in to place it is not attached to the dimension. I looked in the styles editor but could not find the setup option I need.
View 8 Replies View RelatedWhat is the best way to measure angular displacement on a FEA simulation?
A simple example is described here: The screen shot shows a long rigid body (left) mounted on a bracket (far right). The legs of the bracket are fixed on the right. There is a down force on the left. The goal is to measure vertical displacement on the left. All of the vertical displacement comes from flexing at the bracket, so this can be considered an angular displacement.
Is there a way to measure this vertical displacement without the long rigid body or it's mesh elements?
Or is there a way to turn off the mesh elements on the rigid body? I want to eliminate the unnecessary FEA computations to speedup the simulations.
We are projecting a support for one mirror of our Infrared beam line. The support is a block with a rotational weak link and that needs to be rotated about +/- 1°. I would like to know a way to insert this angular displacement and get the stress in the weak link area. I don't have the moment loads and components.
View 1 Replies View RelatedI don't know if this has been reported but I found out today when working on a web design (hence working in the new unit - pixels) that you can't actually use the Dimension tools for measuring pixels. That's a pity because often you need to work with exact pixel dimensions when making websites and here the Dimension tools could come in very handy. It seems counting pixels by hand is a bit old-fashioned. Of course you can use calculations, but still...
View 5 Replies View RelatedI want to use the custom unfolding rules using Bend Compensation with an angular reference to the bending angle.
I have an Excel sheet where I have determined the bend allowance, the set back and from that, the bend compensation. When I compare these values to the values I get when using a K-factor linear unfolding method in Inventor, I get almost exactly the same results.
Tells me the formulas are working. So I implement the formulas in the custom equations. Exactly the same as in the Excel sheet. 10 degrees angle, great results! Yeah! 45 degrees, great results! More yeah! 90 Degrees, still going strong, I think I might make it!
100 degrees.... Fail! Every time an angle goes over 90 degrees, the result is crap.
I have been struggling with this all day long!! So in the end I completely erased the equations from the Inventor custom equations.I just say: Compensation is 1 mm. For all angles. This should no room for interpretation.
Again I try. I have a sheet metal part with two legs. A 100mm leg and a 50mm leg. Flat pattern should always be 151mm. Period.
Again, under 90 degrees and on 90 degrees, I get nice flat patterns. Above 90 degrees, it fails again.
Am I completely overlooking something obvious?? Or is Inventor really bugging on this?
I am working on 2012 SP 2
Why are annotative dimension always placed in model space to the created height regardless of the annotation scale I use. using annotation 1:1 or 1:10 or 1:50 my dimension is always inserted to the dimstyle hight of 3.5mm (about 1/8") and not 3.5 x annoscale example 10 = 35mm.
When dimensions are placed using an anno scale of 1:1 and than change the anno scale to 1:10 the dimensions and dim arrows ect are scaled to the correct size 10x value preset in the dimsyle. My text style is non associative and set to 0.0 height.
The only way i can place dimensions to the preferred height is linked to the anno scale is by setting the text style height 3.5 (about 1/8"). but the problem here is that the dim text height will be displayed to selected annotation scale of 1:10 but the dim arrows etx are not to size. I know that setting the text style hight is not the correct way and see why.
All my dimension styles are annotative and and have the ANNOAUTOSCALE set to 1. I have also tried by presetting the object anno scale to the preferred annotations.
I have one problem in ilogic "How to convert the normal dimension to driven dimension through ilogic"
View 4 Replies View RelatedUpgrading to a new computer.
1. What is the best CPU to use for Inventor between the i7 and the a Dual Xeon System
2. Would 32GB of memory easily cover all modelling such as assemblies?
3. Any advantage of having 2 x SSD instaed of 1 x SSD
4. Looking at the Nvidia GTX690 graphics card....this should be a good card