why after selecting Dimension, Angular, then selecting two lines, I do not get the angle between them? I am using v 2000 if it matters. I enclose a screen shot of the two lines I need the angle of.
I have a block of a guide sign with directions and azimuth angles. I made arrows rotatable and angles were changing ok. But when I try to rotate an arrow into zero position, dimension shows 180. I need the dimension to show 0 degree. How can I do it?
And I can’t make angular dimension show degrees greater than 180 even if I specify vertex – after rotation angle shifts on the other side. I gave up and used back azimuth.
And I can't make an attachment: "The contents of the attachment doesn't match its file type"?
I am trying to put an angular dimension from a hole to a slot positioned planes 90degrees to each other. How can I achieve this? Typically, it depends on how it is put into the ipt file but I didn't know how else to put the slot in therefore only a point was put in at that angle.
The only formats I see for angular dimensions in the toolbox are degrees, °, radians, gradians. Is there any way set angular units be deg-min-sec (° ' ") format?
I cant get a dimension to work in the vertical (Z) plane. i have a cube and can get dimensions to work properly in the x*y plane (horizontal) but when i try to dimension the vertical side autocad refuses to dimension anything vertical, all i get is a horizontal dimension of the distance between the 2 points i have selected vertically, set down on the horizontal plane. tried to get it to work in 3d workspace and also the 2d annotation & dimensioning workspace -no joy...
I set a "limits" in my drawing(command "limits"-- "lower left corner is 0,0" --- upper right corner " is set as 20, 20--enter)
But then I moved my mouse horizontally and vertically on the screen, and found that the coordinate value at the bottom was from -25 on the left to 18 on the right, and from 0 at the bottom to 15 at the top. I am confused about what on earth does that limit? should it be 20 in length and 20 in width?
If you can make lisp for angular dimension when i have profiles x scale 1-500 and y scale 1-50 and i want when draw angular dimension take scale 1:1 x & y.
Is it possible to have text below the angular dimension line like you can with most other dimensions. The attached pic shows my 10 dimension with the type. Under the line and my 30 dimension with type. Under the line but the type. Under the 30 is just a text box I eye-balled in to place it is not attached to the dimension. I looked in the styles editor but could not find the setup option I need.
What is the best way to measure angular displacement on a FEA simulation?
A simple example is described here: The screen shot shows a long rigid body (left) mounted on a bracket (far right). The legs of the bracket are fixed on the right. There is a down force on the left. The goal is to measure vertical displacement on the left. All of the vertical displacement comes from flexing at the bracket, so this can be considered an angular displacement.
Is there a way to measure this vertical displacement without the long rigid body or it's mesh elements?
Or is there a way to turn off the mesh elements on the rigid body? I want to eliminate the unnecessary FEA computations to speedup the simulations.
I have a 2D drawing that I used presspull to give the correct depth to. Now I have to make modifications to it that are angular to the presspull direction and am not sure that presspull is the correct way to do it. I've searched around for vids and have looked at quite a few, but am stumped. Don't know if I need to change the orientation so that the angle I want to cut is the direction for presspull or if I am simply looking at the problem wrong. If I knew how to take a screenshot, I would post some so that it would be clear how inept I am.
I am wondering if it is normal for the lines to be jagged. Vertical and horizontal lines are straight but the angular ones are jagged, Stair step looking whatever you would call it. It makes the stuff I draw look like (edited) .Especially the low angle stuff.
We are projecting a support for one mirror of our Infrared beam line. The support is a block with a rotational weak link and that needs to be rotated about +/- 1°. I would like to know a way to insert this angular displacement and get the stress in the weak link area. I don't have the moment loads and components.
how to sensibly extract angular dimensions as attributes.
I can extract the attributes from a block containing angular dimensions, the attributes list angular dimensions as a field but don't actually list the number of degrees for the angular dimension.
It is the number of degrees that I am actually trying to obtain - but I cannot work out how to obtain the information
I am trying to create a lisp file to automate the placing of angular dimensions at all of the vertex's along a very long polyline. There are 500-600 nodes at least and we need the angle between the incoming and outgoing lines at every node.
Is there a way to automate this with a lisp file, or am i relegated to clicking 1800 times and waste 3-4 hours doing this?
We get these files quite often and this will be a huge benefit to us.
I want to use the custom unfolding rules using Bend Compensation with an angular reference to the bending angle.
I have an Excel sheet where I have determined the bend allowance, the set back and from that, the bend compensation. When I compare these values to the values I get when using a K-factor linear unfolding method in Inventor, I get almost exactly the same results.
Tells me the formulas are working. So I implement the formulas in the custom equations. Exactly the same as in the Excel sheet. 10 degrees angle, great results! Yeah! 45 degrees, great results! More yeah! 90 Degrees, still going strong, I think I might make it!
100 degrees.... Fail! Every time an angle goes over 90 degrees, the result is crap.
I have been struggling with this all day long!! So in the end I completely erased the equations from the Inventor custom equations.I just say: Compensation is 1 mm. For all angles. This should no room for interpretation.
Again I try. I have a sheet metal part with two legs. A 100mm leg and a 50mm leg. Flat pattern should always be 151mm. Period.
Again, under 90 degrees and on 90 degrees, I get nice flat patterns. Above 90 degrees, it fails again.
Am I completely overlooking something obvious?? Or is Inventor really bugging on this?
I'm trying to get the dimension text that I pull out to the side closer to the actual dimension marks. The 2 1/2" and 2" shown have a minimum distance they can get toward their dimensions. I would like it to be about half of what it is, but so far I haven't been able to find the property that changes that.
Is it possible to override a dimension with some sort of formula or function that relates to the length of the dimension?
A simple linear scaling might be possible by inventing a new unit with the appropriate conversion ratio, but that wouldn't work. What I need for the dimension to display a length 400 less than the actual length.
I'm trying to figure out how to accurately display the current rotation angle of an object in DRAW X6. Based on my drawing precision settings, the angular accuracy is there, but it's not properly displayed.
IE - If I type in 5.05 deg rotation, it will DISPLAY 5.1 but will actually be 5.05.
Is there a way to update the display to show more than one decimal place for rotation?
Is there a way to override a dimension and have it shown as a GD&T Basic dimension. I can override a dimension with the text option but not with a box around the letter. It sounds strange to do this but the letter represents a dimension in a chart format that are Basic dimensions.
I want to insert dimension lines on this project. But instead of having an actual dimension I'd like it just to be a letter that refers back to a chart of possible dimensions for that element. How do I do this? I'm using AutoCad Architecture 2012.
Can i change the length of the dimension line 'extension' when my dimension text placement is beside the dimension line (see attached image)?dim line length.jpg