AutoCAD Inventor :: Use Custom Unfolding Rules With Angular Reference To Bending Angle
Aug 7, 2013
I want to use the custom unfolding rules using Bend Compensation with an angular reference to the bending angle.
I have an Excel sheet where I have determined the bend allowance, the set back and from that, the bend compensation. When I compare these values to the values I get when using a K-factor linear unfolding method in Inventor, I get almost exactly the same results.
Tells me the formulas are working. So I implement the formulas in the custom equations. Exactly the same as in the Excel sheet. 10 degrees angle, great results! Yeah! 45 degrees, great results! More yeah! 90 Degrees, still going strong, I think I might make it!
100 degrees.... Fail! Every time an angle goes over 90 degrees, the result is crap.
I have been struggling with this all day long!! So in the end I completely erased the equations from the Inventor custom equations.I just say: Compensation is 1 mm. For all angles. This should no room for interpretation.
Again I try. I have a sheet metal part with two legs. A 100mm leg and a 50mm leg. Flat pattern should always be 151mm. Period.
Again, under 90 degrees and on 90 degrees, I get nice flat patterns. Above 90 degrees, it fails again.
Am I completely overlooking something obvious?? Or is Inventor really bugging on this?
I am working on 2012 SP 2
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Nov 2, 2012
Is Inventor able to provide information about the bending angle of a lofted pieces ?
I'm trying to loft a piece from square to circle. The bender ask me what is the angle of this pieces.
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Oct 20, 2011
Is there any way possible to have an angular dimension to denote an angle of greater than 180 degrees?
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Oct 29, 2012
I have a 2D drawing that I used presspull to give the correct depth to. Now I have to make modifications to it that are angular to the presspull direction and am not sure that presspull is the correct way to do it. I've searched around for vids and have looked at quite a few, but am stumped. Don't know if I need to change the orientation so that the angle I want to cut is the direction for presspull or if I am simply looking at the problem wrong. If I knew how to take a screenshot, I would post some so that it would be clear how inept I am.
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Sep 10, 2013
I have a custom elbow that has an angle of 89° in the tube and pipe author dialog but I cannot select it in the tube and pipe style in the "elbow custom" field where the filter properties are 45° to 90°. I can select it as the standard elbow though where the filter properties are 90° to 90°. This doesn't make any sense. All the other filter properties (grayed out) are the same.
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IV2013
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Oct 1, 2012
Is there any way to use the "Rotate at angle" command outside of the "custom view" environment?
Is there actually any technical reason why the controls in the attached screenshot are not available in the Studio and normal modelling environments?
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Dec 18, 2013
Attached are two sheet metal parts that we need to unfold and make them flat for a drawing. We cannot seem to capture the reference A or reference B planes asked for by the unfold command.
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Dec 5, 2011
I'm unfolding a 30x40x2 mm square tube for tube laser. The tube is imported from STEP format.
The flat pattern is 1,5 mm too narrow - even when I increase the K-factor to 1,0.
Is there any work around to get a wider flat pattern.
IV 2010
HP-Z200 Pentium 3,3 GHz
12 GB ram AtiFirePro V-4800
Windows 7-64 Pro
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May 11, 2011
For some strange reason I can not print and dimension lines with an angle reference. I get the error "Cannot find or create the font AerialMT".
However, I have this font on my machine. Triple checked and installed it again.
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Oct 4, 2011
I drew a very funky bracket in IV 2012. I tried using the sheet metal features but they wouldn't cooperate with the funky geometry. I ended up having to draw to sketch profiles, lofting to create a thin feature, and thickning it to material thickness. But this left me without any real bends that the unfold tool can recognize. I tried using the unfold tool (I know that's not what it's for) but it gave me some very funky geometry. I tried ripping out the lofted bends, which worked great, but that leaves me with twisted edges that the bend tool can't grab. how to either model this using the sheetmaetal tools, or how to make this thing unfold?
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Dec 14, 2011
I am constructing a pipe (made up by sections) in Inventor. The pipe is going to be manufactured by cutting pieces of metal in a flow jet, roll them, and eventually weld them together.
I was wondering if it is possible to "unfold" the pipe sections to the plane, so I easily can see the cutting lines for the flowjet?
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Jan 11, 2013
I am using Inventor Professional 2013 what im trying to do is create a flat pattern so I can send out to get formed. I need the panel to be 7.75" Width 53.50" Height and 2" Depth. When I click unfold where the 45deg is, it doesnt match up with the bend. Im not sure if its supose to be like that or what lines i need to keep to get the correct mesurments.
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Aug 15, 2012
I have a very simple solid that consists of a lofted solid that was the "hollowed" out via the Shell command
The sketches used to make this lofted solid were two dimensionally similar rectangles. One has radiused corners while the other does not. These rectangles exist on 2 separate planes that are 10" apart. This part (Shroud1.ipt) is supposed to represent a shroud that will be installed between the intake and exhaust of an air filter.
I wanted to convert this to a sheet metal part and then unfold it so I could see what the flat pattern looked like. However, when I attempt to use the "Unfold" command it fails. Similarly, the Flat Pattern command fails as well.
What do I need to do to get this into a flat? I'd rather not redraw this as a sheet metal part. I'm not that familiar with that environment.
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Sep 23, 2011
I have tube that has been generated on frame generator and notched to run into the side of another tube.
Is there anyway of unfolding the tube to provide a flat profile.
What i ultimately want to do is print the flat pattern off at 1:1 scale, cut it out and wrap it around the actual steel tube to be able to trace the profile onto the tube so i can cut the profile roughly before offering the two tubes together.
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Feb 22, 2013
I have been trying to unfold round tubing made through the frame generator. Here are the steps I took:
1. Used Frame Generator
* both ends of the tube are notched
2. Opened part and converted into sheet metal
3. Used the following tutorial: URL...
4. Was not working so I drew sketches on both ends of the notched tubing and added points
5. Used rip tool (point to point) and did not work
* I made sure the thickness was the same
I thought I was doing something wrong so I generated a new round tubing frame with only 1 end notched and the other end flat and followed the tutorial. IT WORKED! I have came to the conclusion that you can not use the rip tool on tubing that has both ends notched.Is there a way where I can cut the tubing in half so I have 2 individual pieces/files of tubing with 1 end flat and 1 end notched?
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May 10, 2012
Autodesk Inventor Professional 2011
Sheet Metal
I need to know the Kfactor to use for folding and unfolding Nickel Alloy 200 - 1/4 hard.
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Oct 7, 2013
I am trying to unfold a part created from a derived assembly like I usually do… why in the world will it not unfold, and show a preview of the unfolded in the other direction??
At first all was working… until I added a part (see the circled item in picture), and I don’t have any problem usually!
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Oct 3, 2012
Is it possible to have text below the angular dimension line like you can with most other dimensions. The attached pic shows my 10 dimension with the type. Under the line and my 30 dimension with type. Under the line but the type. Under the 30 is just a text box I eye-balled in to place it is not attached to the dimension. I looked in the styles editor but could not find the setup option I need.
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May 26, 2013
I have used a driven contraint in a sketch.
Can that also be done in an assembly?
In one assembly I want to make one angle half of a driven angle.
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May 13, 2013
What is the best way to measure angular displacement on a FEA simulation?
A simple example is described here: The screen shot shows a long rigid body (left) mounted on a bracket (far right). The legs of the bracket are fixed on the right. There is a down force on the left. The goal is to measure vertical displacement on the left. All of the vertical displacement comes from flexing at the bracket, so this can be considered an angular displacement.
Is there a way to measure this vertical displacement without the long rigid body or it's mesh elements?
Or is there a way to turn off the mesh elements on the rigid body? I want to eliminate the unnecessary FEA computations to speedup the simulations.
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Sep 9, 2012
is there any way I can place dimension on drawing that would be in dual units (in decimal degrees and in deg min sec)?
I did not find this possible so far.
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Dec 17, 2012
We are projecting a support for one mirror of our Infrared beam line. The support is a block with a rotational weak link and that needs to be rotated about +/- 1°. I would like to know a way to insert this angular displacement and get the stress in the weak link area. I don't have the moment loads and components.
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Mar 26, 2012
I am trying to put an angular dimension from a hole to a slot positioned planes 90degrees to each other. How can I achieve this? Typically, it depends on how it is put into the ipt file but I didn't know how else to put the slot in therefore only a point was put in at that angle.
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Jul 15, 2011
I have not had any luck finding support on Auto Cad Architectures Keynoting w/ data base.
The issues I can't seem to resolve are: formatting the reference legend and saviing the format so I can re-use it in all my drawings creating a custom reference keynote?
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Jul 16, 2012
I am trying to run a 4 points bending simulation on a concrete beam but i can't create the 2 support points on the bottom side. Is there an option that i could use or a tutorial that explains the process?
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Sep 7, 2013
How do you set an object's annotation, say a line, to display a line's angle or bearing precision to the nearest 20th second.
Kinda like this for decimals:
0.000
0.00
0.0
But for degrees minutes seconds.
Also, I will require the seconds to hide if the nearest 20th second was a 00. I also need a leading zero for minutes if the minutes was under 10 minutes.
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Mar 14, 2013
i'm looking to select a block reference, take it's wcs position, translate the coordinates to the current ucs and then create an xline using those translated coordinates. simple, right?
i simplified some code to test that i could properly build an xline in a current ucs. i just threw in static point3d values instead of grabbing them from another object. it worked as expected:
<CommandMethod("test")> _ Public Sub test() 'get the active document, editor and database Dim acDoc As Document = Application.DocumentManager.MdiActiveDocument Dim acDocEd As Editor = acDoc.Editor Dim acCurDb As Database = acDoc.Database 'start a transaction Using acTrans As Transaction = acCurDb.TransactionManager.StartTransaction() 'open the table for read Dim acBlkTbl As BlockTable acBlkTbl = acTrans.GetObject(acCurDb.BlockTableId, OpenMode.ForRead) 'open the record for write Dim acBlkTblRec As BlockTableRecord acBlkTblRec =
[code]...
here, i revised the code so that a block reference's objectid is passed from another procedure, the origin is determined, translated to the current ucs and the points are tailored for the xline's basepoint and secondpoint. i threw in a few writemessages to ensure that the coordinates were indeed what i was looking for and they match up, but for some reason, the xline now fails to create itself.
'define the current ucs Dim ucsDesign As Matrix3d = acDocEd.CurrentUserCoordinateSystem 'start a transaction Using acTrans As Transaction = acCurDb.TransactionManager.StartTransaction() 'open the connector block for read Dim acBlock As BlockReference = acTrans.GetObject(idConnector, OpenMode.ForRead) 'save connector origin Dim ptOrigin As Point3d = acBlock.Position 'translate the point to the current ucs Dim ptUcsOrigin As Point3d = ptOrigin.TransformBy(ucsDesign.Inverse) 'show me the block position acDocEd.WriteMessage(vbLf & ptOrigin.ToString()) acDocEd.WriteMessage(vbLf & ptUcsOrigin.ToString()) 'open the table for read Dim acBlkTbl As BlockTable acBlkTbl = acTrans.GetObject(acCurDb.BlockTableId, OpenMode.ForRead) 'open
[code]...
i've rearranged this code multiple times, tried a couple different approaches, scoured the forums and even resorted to the less-than-elegant:
'create the xline Dim cmdString As String = "._xline " & ptUcsOrigin.X & "," & ptUcsOrigin.Y & "," & ptUcsOrigin.Z & " " & ptUcsOrigin.X & "," & ptUcsOrigin.Y + 1.0 & "," & ptUcsOrigin.Z & " " acDoc.SendStringToExecute(cmdString, True, False, False)
but i need to use the xline object after i've created it, so this sendstringtoexecute crap won't work.
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Aug 13, 2013
I was wondering if there is a way to bend a derived componet. I have an odd extruded part and would like to cut and bend it. I want to do it this way so I can also include the cut length before bend. I know of frame generator, but am not able to use it since if falls out of the structure of how our files are saved.
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Nov 24, 2011
I've created several (4) ilogic rules and want to run them by pressing a button. So I need a form with 4 start buttons. Can I create this with Ilogic in Inventor 2011 or do I need to be VBA expert?
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Jun 6, 2012
how i can add .net code on reference editing and refedit command.
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Jun 28, 2012
Having problems using custom pipe properties in pipe label expressions in 2013? I have some expressions relating to stub callouts and the ones that directly reference the custom properties lose that reference every so often.
For example I have and expression called "STUB-Riser-Length2d" which is defined as "{Riser Length} / SQRT(2)" where "Riser Length" is the custom pipe property. Every week or so it changes to "/ SQRT(2)".
I haven't been able to find the pattern as to exactly when this happens yet. All expressions not referencing custom properties seem to be holding steady. The pipe catalog is on a shared drive on the network, if that makes any difference.
Civil 3D 2013 - Windows 7 Pro 64 - Dell T3500 - Xeon 2.67 - 24gb - Quadro 600
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