AutoCad 2D :: Rotate An Object To Match An Angle Without Knowing The Angle?
Oct 5, 2011
Is there a quick way to rotate an object to match an angle without knowing what the angle is? I am using AutoCAD 2011 now. I was using 2007 and I had an add on command the would rotate an object using a base point and picking the two lines that make up the angle, and it would match the angle you wanted. I can not get that command to load in 2011.
I have a property line that is N 36d19'52" E but needs to be N 12d52'18" E. The obvious and calculated rotation angle would be 23d27'34" but when I rotate the line by the calculated angle it doesn't rotate to the right angle. It's off by 0d11'10"!? When I draw a line by bearing at N12d52'18" E and inquiry the angle between the property line and the drawn line the angle difference is in fact 23d27'34".
i would like to rotate an object to match the angle of another. I can measure the angle but there are many decimal points and I want it to be exact.
One method i have employed is to change the ucs - z setting to align with the object to be rotated then click it and select a point that intersects the other object (this case a line) and then the 2nd snap is somewhere along the line.
this works although sometimes i have to rotate a second time 90 deg. or 180 to get proper orientation.
How do I rotate an object in Illustrator without chaging the angle of my drop shadow? I have a design that I want to place 2 up on a page and then print. When turn and stack them the shadow has changed its angel in relation to the artwork. I don't see where to lock the drop shadow to the object. Or is it secified a different way?
I want to rotate object along circle with special step angle. If i choose TRANSFORM i don't type special angle, but i can choose pivot point. I don't know how name this point, i name this pivot point, the point concerning which object rotates. And if i choose TRANSFORM OPTION i can type special angle, but i can't choose pivot point. More precisely, i don't know how do that. I choose object, then transform, set pivot and then open pivot option, type angle but object rotate around own pivot!!!
Let's say I am inserting a square block into a dwg and want to get it parallel to an existing angled line. Do I have to read the angle of the line and insert the block to that angle or is there a quicker way?
how to convert "real world" angles of elliptical arcs into those shown in a dxf file?
Say that I have drawn an elliptical arc with its start angle on 210 degrees and an end angle of 324 degrees. The values in a DXF file, for an elliptical arc, have something to do with the contant "PI" (3.14159). I know that a full circle is 2*Pi but how to do this with elliptical arcs!!
Matrix3d cur = ed.CurrentUserCoordinateSystem; Vector3d x = new Vector3d(1, 0, 0); Vector3d y = new Vector3d(0, 1, 0); Point3d o = new Point3d(0, 0, 0); [Code] .....
Code is rotating well my model, but it's zooming to bad point. I want to zoom to the point from previous view, so I'm transforming it by new UCS - unfortunately something is going wrong (it's not this point what I want).
I'm making this diagram of the load condition acting on tunnels to explain a Japanese set of equations that are used for the structural analysis for tunnels:
load condition for EEM.jpg
But, there is one problem I have. I'm trying to set up the text for the dimension between the water table and the tunnel "Ha" to look horizontal.
However, if I click on the properties box and write 90 in the rotation box right next to where it says "text rotation," the dimension text does not rotate 90 degrees; if instead I try to rotate it 180° then it only rotates 90° (and in the opposite direction) instead of 180°. It doesn't matter how many degrees I choose, it won't rotate my dimension "Ha" to desired angle to make it look horizontal.
OK I know it's hard to explain my problem with just writing, so I've posted a few pictures:
In this one, the dimension is at 0°; I've only opened the properties box to attempt and rotate it: no rotation.jpg
Now I write 90 in properties box but the dimension text does not rotate at all; it remains at 0 as it is shown in the following image: 90 & no rotation.jpg
Next I try to rotate 180, just to see what happens; and it does rotate (only 90 degrees!): 180 rotates 90.jpg
I finally try to rotate the text 270 just to see if it rotates to desired angle and it does rotate (180 degrees from original position). As shown below:
270 last try.jpg
It doesn't matter how many degrees I choose, I cannot make it look horizontal.
How can I set up my dimension text "Ha" to look horizontal?
I'm looking for a lisp routine that allow me to select a text object that is rotated to anything other than zero, and it will change the text object to zero rotation and while still in the command allow me to place the text object on the screen.
I have a routine that is similiar called RT180 but it just rotates whatever text object you select 180 degrees from its current rotation, but I can not figure out how to modify it to rotate to zero rotation angle. What I like about RT180 is that you select your text it rotates it on the spot and then lets you pick a spot to place it.
Is it possible to rotate a viewport to an angle other than 90 degrees. I am trying to rotate a viewport 11 degrees counter clockwise. I cannot rotate the model.
In Graphics Editing software like Photoshop you can rotate an image ever so slightly to the left or to the right. I'm trying to super-impose a png of a head onto something and I would like to match the angle of the original head.
I'd like to orient a picture of a book so that it's on a 45 degree angle and then "cut out" the area around the "book" to that when you view the picture is looks like a book on a 45 degree angle with no area around it. I'm sure GIMP can do that but the question is whether I can put that same photo on a website and have it look like it's a book on a45 degree angle.
How do you set an object's annotation, say a line, to display a line's angle or bearing precision to the nearest 20th second.
Kinda like this for decimals: 0.000 0.00 0.0 But for degrees minutes seconds.
Also, I will require the seconds to hide if the nearest 20th second was a 00. I also need a leading zero for minutes if the minutes was under 10 minutes.
I'm trying to figure our how to taper a circular object 1-1/2" high on a 45 degree angle from the top down (that is the lower part goes in like a pie pan). Taper doesn't seem to work.
Illustrator CS6, menu object, transform, move: when I move an object using orizzontal value and vertical value (example 10 mm from X and 10 mm from Y) the value in distance and angle is correct (14,1421 of distance and -45° angle) but, when I want to use distance and the angle for drawing in isometric way (example: 10 mm distance and 30° angle) the orizzontal and vertical value is not correct as you can see in the attached file below
when i change the angle of an object it effects the whole project, so if i have selected an circle and put the angle of a drop shadow to 90 degrees then i selected a recltangle and set drop shadow angle tp 120 degrees the circle will change to also be 120, does it always do this or am i just doing something wrong?
I am using Illustrator CS6. When I select an object and open the Move window (either by pressing the Enter key or selecting Object>Transform>Move), I try and move the object at a given angle and a given distance. I leave the Horizontal & Vertical dialogs blank and just fill in the information for the Distance and Angle. When I press OK (or Copy), nothing happens. In all previous versions of Illustrator, this feature worked perfectly. I can not get it to work in CS6.
Almost every time I add a linear gradient to an object I want to change the angle from 0 to 90 degrees.
Is there a script that I could use for this, so that I could assign a keyboard shortcut and press that instead of clicking the box & typing 90 all the time? (i.e. select an object, run a script & it would apply the standard black to white linear gradient at 90 degrees instead of 0.)