AutoCAD Inventor :: Container Sq Area Calculation Verification?
Sep 26, 2011
I am trying to calculate the area of our parts. I was trying to do the math my self but I kept getting a lower area than IV. I haver attached a picture of what I get from IV. I have listed my calculations of the angle iron below:
I am using IV Pro 2011 Educational SP1
i7 2600
8GB ram
1Gb GTX 560
Cart 72 lbs 4006 sq in
All calculatoins are in ^2
(4) 2x2x1/8x48=92.928, 371.712
(4)2x2x1/8x33=63.888, 255.552
(4)2x2x1/8x29=56.144, 224.576
(2)2x2x1/8x32.669=31.623592, 252.988736
(4)2x1/8x2=32.912
Total = 277.495592, 1137.740736
I don't use the area calculation tool that much. I was just working out a large area for concrete. I use TOOLS - INQUIRY - AREA. Thats all fine and it gives me the area, for instance, to keep it simple 4900 x 9000 = 44.10m² AutoCad displays it as 44100000. I know it's not a major problem, but is there anyway I can get it to display as 44.10 or at least lose all the zeros.
how the area calculation works for finding the square footage of a dwg.
I can easily get a rough estimate of square footage on L X W....but when i use the area measuring tool, i get total inches and a total sq foot estimate of 1.7xxxxx which i don't understand.
I am highlighting an area and at the last point where I press eneter expecting an area calculation, I get this message "specify next point or [A/L/U]; I don't want that I want the area
I was just wondering why when I try and calculate an area using a polyine, I am getting a readout of 1.80401967E+07, when I have it set to give me the calculation in square feet? It is an area of approx. 246 Acres.....is this because the area is so large? I am not sure what the "E" stands for or the "+07" at the end....
My company recently installed Inventor 2013. In previous versions we used a part with negative density similar to seawater to calculate submerged weight and CoG.
In IV 2013, it seems that the ability to calculate negative mass is not longer available.
This is how it worked in pre 2013 IV, when I could specify a negative density.
What I have is a spool made of steel. This spool is modelled as an iAssembly with four configurations:
-In air, empty
-In air, filled with glycol
-Submerged, empty
-Submerged, filled with Glycol
For this example, I now need three parts:
-Steel Pipe
-Glycol derived from the inside volume the pipe
-Seawater buoyancy derived from the outside volume of the pipe.
Each part has its own density, and the assembly weight and CoG correspond to the assembly configuration (with or without glycol) and environment (in air or submerged).
The seawater buoyancy represents the water displaced by the total spool assembly, regardless of the contents. To achieve correct weight in the submerged state, the buoyancy material has to have a negative density.
I do not want to make any of the mass parameters static, and I also fear that the CoG might not be updated correctly when using that method.
As I no longer can define a negative density, any optional method to achieve this without overriding the mass value.
I would like to know what calculation on the length of a folding feature is performed by Inventor when one folds it. Read my example to better understand my question.
I am trying to fold a part of my sheet 90 degrees, I am going to call the folding part sheet B and the rest of the sheet, sheet A. Now, understand that when I fold sheet B 90 degrees, its face will no longer be parallel to sheet A, but the face of its thickness will. Consider this, now: when I fold the sheet B, there will be an inner part of the folding (which will have the faces of both sheet sections 90 degrees from each other) and the outer part (which will have an angle of 270 degrees between them).
I want the distance between the thickness face and the outer face of sheet A to be X in length. Which is the intial length of sheet B for this to happen? Consider using the BendRadius, Thickness, and other Inventor Sheet Metal parameters that will participate in the equation.
The question surged because I wanted such distance to be 5 in a part with a Thickness setting of 0.5 (as well as BendRadius), but because of this folding length calculation, I had to make sheet B 5.631 in length.
I've has Inventor tell me this for thin walled tubes with holes in them, but not for a simple part like the attached one. Autodesk are you listening yet? This has been an issue for a long time. Mass calculations for parts with holes on curves do not work properly. On many parts the error comes up with "low" selected. By default each time I try to save the file, the error window pops up.
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After Effects Error: internal verification failure! {Plugin ID is invalid}
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Win 7 Ultimate 64bit 16gb ram cpu: q9550 @3.99ghz gpu: gtx770 60gb ssd with os and ae + 4tb hdd (1tb+1tb+2tb)
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When I have Draw open on the desktop, The little green icon in the bottom left is there and shows tha I am signed in. However, when I am on my laptop, the icon is not thre at all. When you go to the help button and look - it says "sign out" which would indicate that I am signed in...
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How do I stop this from happening....is there a way to edit the settings?
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