I've has Inventor tell me this for thin walled tubes with holes in them, but not for a simple part like the attached one. Autodesk are you listening yet? This has been an issue for a long time. Mass calculations for parts with holes on curves do not work properly. On many parts the error comes up with "low" selected. By default each time I try to save the file, the error window pops up.
View 8 RepliesHow to set the mass calculation accuracy to 'Very High' when doing calculations in iLogic.
I asked for the iLogic equivalent to the VBA term:
' Set the accuracy to VeryHigh.
oMassProps.Accuracy = k_VeryHigh
and was provided with:
oMassProps.Accuracy = 24580 'k_VeryHigh=24580
However, I believe that the value 24580 is actually equivalent to k_Medium. Confirm the iLogic equivalent value of k_VeryHigh.
Original post: [URL].......
My company recently installed Inventor 2013. In previous versions we used a part with negative density similar to seawater to calculate submerged weight and CoG.
In IV 2013, it seems that the ability to calculate negative mass is not longer available.
This is how it worked in pre 2013 IV, when I could specify a negative density.
What I have is a spool made of steel. This spool is modelled as an iAssembly with four configurations:
-In air, empty
-In air, filled with glycol
-Submerged, empty
-Submerged, filled with Glycol
For this example, I now need three parts:
-Steel Pipe
-Glycol derived from the inside volume the pipe
-Seawater buoyancy derived from the outside volume of the pipe.
Each part has its own density, and the assembly weight and CoG correspond to the assembly configuration (with or without glycol) and environment (in air or submerged).
The seawater buoyancy represents the water displaced by the total spool assembly, regardless of the contents. To achieve correct weight in the submerged state, the buoyancy material has to have a negative density.
I do not want to make any of the mass parameters static, and I also fear that the CoG might not be updated correctly when using that method.
As I no longer can define a negative density, any optional method to achieve this without overriding the mass value.
Autodesk Product Design Suite 2013 SP1
Win 7 Enterprise 64bit
Intel Xeon CPU E3-1240 V2 @ 3.40GHz
16Gb Ram
Nvidia Quadro 2000
I am having a problem with an assembly not showing the correct total mass of all of its components and sub-assemblies. The value is out by nearly 20%, over 3000kg!
I have narrowed the mass discrepancy down to a derived part of a sub-assembly. But this incorrect mass is only present when I navigate to the derived part's iproperites via the browser tree of the higher level assembly where I am having the mass problem. It is as though the top assembly got some of its mass property information from a previous point in time, i.e. possibly before the derived part's mass properties were updated, and now refuses to look at the current information.
By the way, I have opened up and checked the mass properties of each sub-assembly and the derived part; and when opened individually these show as correct. I have also tried 'Rebuild All' with no success.
Is it possible for mass properties in an assembly to become corrupted?
I have a .iam and .idw that i copied/designed from vault. The .idw has a sketched symbol that has a text box with the mass property. When update mass is applied the mass property in the text box does not. I ran into this once before and got it to work by re-inserting the symbol into the .idw but I can't get it to work. The orginal that was copied from works fine.
IV2013
Vault Collaboration 2013
I have a routine that looks for an MText date stamp and replace the old date with a new date. The problem is some MText strings appear encrypted. Below is an example:
{\H1.121x;\C1; \LFY 2011-12\l \H0.6252x;04-30-11} This is what I should get when I extract the string (as shown in Property window)
(1 . "\pxi-2.1818,l4.3636,ql,t4.3636;{\fSymbol|b1|i0|c2") is what I get when I extract the group code.
I'm running AutoCAD 2012 on Windows 7.
Is there any way to set the drawing accuracy in INV2013.
Like not to calculate the points more than 3 decimals.
I've been looking for a solution to remove the unit string ie Lbs, g, kg from the value given from a 'Mass' value in a text string.
As you may all know, creating text and having a 'physical property - mass' value...the unit string is there...
Lots of people on here have the problem...no-one has got a solution.
Until now...
Basically...open the part you need to get the mass property of in your text string.
Follow the instructions on this webpage...this is the first part...
[URL]
Basically, this creates a Mass property value in the parameters table that you can call on as a text parameter.
It's similar to the custom iproperty model - mass but NOT the same.
Once you have done this, you can go to the drawing of the part and create a text string in the drawing and call it up as shown in this procedure. BUT it still has the unit string.
Here's the best bit that you want to know...
To get RID of the unit string...open up the part again from the drawing...click on the parameter icon...find the user parameter...in the Nominal value column, right click on the value and you get a pop-up that gives you 3 options...
Custom Property Format, Make Multi Value & Delete Parameter.
Click on Custom Property Format.
The pop-up window comes up...showing you the property type...in my case...the 4 left columns read Text, g (grams), Format & Precision...
On the right hand side I have a Preview of the text...then 3 check boxes...Units string, Leading Zero's, Trailing Zero's.
Units string is checked.
Uncheck it.
Close it...Save your part...go back to the drawing and hey presto!...the text now shows the weight you require as a straight value...no units!
In the attached report, safety factor is se to calculate from ultimate tensile stress (485 MPa), and it indicates 1.33 with stresses:
Von-Mises: 323 MPa..............SF = 1.5
1st principal: 303 MPa.............SF = 1.6
2nd principal: -181.2 MPa....... SF =2.67
So, how is inventor getting 1.33 ?
EDIT: if I set it to calculate from yield ( 260 MPa) it accurately reports SF = 260/323=0.8
EDIT: added part file
Questions below pertain to using Autodesk Inventor 2013:
What factor of safety value the Shaft Generator program uses when you run the calculations?
Does the factor of safety value change when you are not using the inventor user material option?
Lastly, when exactly do you know when to use the density option in the calculation properties or not?
I am trying to calculate the area of our parts. I was trying to do the math my self but I kept getting a lower area than IV. I haver attached a picture of what I get from IV. I have listed my calculations of the angle iron below:
I am using IV Pro 2011 Educational SP1
i7 2600
8GB ram
1Gb GTX 560
Cart 72 lbs 4006 sq in
All calculatoins are in ^2
(4) 2x2x1/8x48=92.928, 371.712
(4)2x2x1/8x33=63.888, 255.552
(4)2x2x1/8x29=56.144, 224.576
(2)2x2x1/8x32.669=31.623592, 252.988736
(4)2x1/8x2=32.912
Total = 277.495592, 1137.740736
I would like to know what calculation on the length of a folding feature is performed by Inventor when one folds it. Read my example to better understand my question.
I am trying to fold a part of my sheet 90 degrees, I am going to call the folding part sheet B and the rest of the sheet, sheet A. Now, understand that when I fold sheet B 90 degrees, its face will no longer be parallel to sheet A, but the face of its thickness will. Consider this, now: when I fold the sheet B, there will be an inner part of the folding (which will have the faces of both sheet sections 90 degrees from each other) and the outer part (which will have an angle of 270 degrees between them).
I want the distance between the thickness face and the outer face of sheet A to be X in length. Which is the intial length of sheet B for this to happen? Consider using the BendRadius, Thickness, and other Inventor Sheet Metal parameters that will participate in the equation.
The question surged because I wanted such distance to be 5 in a part with a Thickness setting of 0.5 (as well as BendRadius), but because of this folding length calculation, I had to make sheet B 5.631 in length.
How to create a dome using just the surface area?
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How can I see the mass of a solid, or if it's not possible, at least the volume.
View 1 Replies View RelatedI was checking my prints and noticed that the mass for the assembly was not shown correctly. The mass for each component is correct, but the mass for the assembly is less than the total mass of the parts..... how can that be?
Watch this video. The mass for my assembly is reported from iProperties as 10 lbs, but the mass for one of the parts is 60lbs. I would expect the mass for the assembly to be at least 60 lbs, but it is not. I tried a "Rebuild All" and an "Update Mass" on my assembly, but that did not fix it (30 sec mark in the video).
This assembly is part of a much larger assembly (around 35,000 parts). There are several more assemblies doing this and I need to get the mass correct.
I am using 2013 x64, SP2.
I have an assembly that i need to know the mass of, easy enough, however the assembly needs to be weighed without some of the parts in it. I hought i could simply uncheck "enabled" of the unwanted parts and re check the mass, however it does not change. Any solution besides adding the wanted parts individually?
View 6 Replies View Related have one assy comprising of a valve, made in steel, an actuator made in aluminum, total weight combined is 36 kg.
I make this assy a derived ipt.. i have tried all the output options, single solid, multy solid and the weight is not the same.. since its a new ipt has its own material, ok makes sense.. .. So i use composite, i get the correct weight (yay), but now i cant turn the visibility off on the 2d drawing, in certain pipe spool view representations.
What is the correct procedure for turning multi material assys into an ipt.. to get the correct weights and get the drawings to work properly?
In assembly file - BOM - mass property, parts with the same name (part number) i get "VARIES"..Parts have a little bit different mass - 0,167kg and 0,168kg. I do not want to have different part number.
So, i'm going to do something like this in iLogic :
iProperties.MassOfComponent("fi_N1:1")=Round(iProperties.MassOfComponent("fi_N1:1"),1)
it works but is there any way to do it for all parts (hundreds) automagically in the loop (iLogic or VB) ?
I have recently made a bucket for chain (linked) and was looking to put the chain in the bucket for visual purposes and to see if the capacity of the bucket is correct.
I can get the chain linked together, however when rotated round it passes through another piece of chain.
Is there a way in inventor to tell a part/assembly of it’s physical/mass properties? I know you can make something mild steel and get weight etc, however if not constrained it still passes through as if it’s a ghost.
I have added the mass properties and I do not want the lbmass behind it. How do I get rid of it?
View 5 Replies View Relatedi found same topics as my, but i didnt find solution.
Is there any way for mass convert idw files (not same format - A4,A3,A2, ...) to pdf ?
I tried task manager, but i dont have some account for it.
I need to add weight to my parts list and notes for both parts and assy. Is there a way to get the weight parsed out from the model without the "lbsmass", just the pounds number no nomenclature I have a couple of other questions on parts list customization also. Also are these better questions for the customization group?
View 2 Replies View RelatedI'm having trouble getting mass properties of an assembly to display in an .idw. I've tried it 2 diffent ways, custom properties-model "Totalmass" where I type the mass and physical properties-model "mass" where it's automatic with update.. Nothing shows, not even N/A, but in another idw (different assembly) it works. Both text boxes are saved within a sketch that is part of a template. Both idw's use the same template. If I place text on the drawing it self it works.
IV 2012
Vault Collaboration 2012
To get net weight of my parts i have one template that uses the volume x density and to get the gross weight I use the real dimensions of the item (a rectangular plate without any cutting, e.g.) and then calculate x density, this way i can get both weights, and how in the most of times I need the gross, I overwrite the MASS PROPERTIES of each part with my gross weight. It works fine because all the assemblies sum the MASS of each part (that is over writed by the gross weight).
Now my problem:
In many cases when I need to use the same part many times with just a few of different details, instead of copy the part and change it, I use the same part, and in the IAM I use one feature to make this part different (like a chamber, small extrudes or even holes). But now I realized when I do this (feature in the IAM), it doesn't sum all the MASS properties of each individual part anymore ... it recalculate all the mass with the new IAM volume (with all the features)...so, in my BOM I got all the parts with the correct gross weight, but my total mass comes with the NET weight (and considering that I need the GROSS, i got the wrong mass).
Is there a way to change the way that inventor overwrite this mass in the assemblies ? with Ilogic, or even some Inventor's option ?
Is there any way to force an update of mass property values of a component from within an iLogic routine?
I am trying to produce a calibration chart showing the volumes of an irregular shaped object by taking incremental slices off the component and accessing the "volume" of the remaining portion, then writing the the results to an external file - All from within a "For - Next" loop.
The main routine works O.K. but the resultant chart only shows the original starting volume for each slice instead of the required reducing volumes.
I am a novice with iLogic and can only assume that I must somehow "update" the mass properties of the sliced object before reading its new volume on each pass.
How can see visually the center mass of a part or assembly?
When I'm checking in the Iprop., I see the center of gravity coordinates, but it there a way to "see" it (some visual representation)
Inventor 2012 Pro.
I7 workstation
We want to obtain the center of mass of two or more subassemblies within an assembly. How to do it? The subassemblies may or may not be connected to each other directly.
View 9 Replies View RelatedI am wondering if it is possible to do a mass change of all project files at once. What I wish to change is my content center location, template location and style manager file locations. I have all these setup already and tested with one project but I dont want to do it with the other ... LOTS! ... manually unless I must.
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