AutoCAD .NET :: Angle Between Two Lines?

Aug 10, 2011

II am looking for two things...

1) A good explanation of Vector3d.  I have been unable to find a good explanation in the ARX documentation or on the online .Net developers guide.

2) Need getting the angle between two lines.  The lines in question are in an orientaion similar to the greater than operator ( > ).  I have attempted to use the Vector3d.GetAngleTo method to get the angle, but I do not understand it enough to be successful!

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AutoCAD 2010 :: Plotting Lines Using Compass Direction For Lines Angle

Apr 25, 2012

i am doing a simple project making a survey plot for a piece of land that will be broken into subdivision. all measurements are of my starting point. after plotting the starting point i try to draw line that is 113 feet long and at a bearing of N 5d W i have no problem entering this data but when i hit enter it draws a straight line. now i know 5 degrees is much of an angle so i thought maybe it just looked straight and tried to plot the next point which was 542 feet from the last point at a bearing of N 39d E but once again after i put the info in and hit enter or space it would plot a line of the proper length but vertical, not the proper angle i need it at. here is how i would put in the info:

first i choose the lne command and choose my "beginning point" as that starting point for my line then i type 113<N 5d W for the length and direction and hit enter. when i do this it plots a vertical line of the proper length but wrong angle. what am i doing wrong? i have ortho set to off and idk what else to mess with

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Jul 7, 2012

Several people recommended DIMANGULAR. I have some concerns using this method because it is dependent on the precision of angular units in the drawings DIMSTYLE settings. For example, if a drawing file's DIMSTYLE has a precision set to the nearest whole decimal degree or only shows degrees and minutes but not seconds then the angle may appear at a certain angle, let's say perpendicular at 90 degrees. But in reality the angle might be slightly less than 90 degrees, if its off by a few seconds.

I learned an alternative way by selecting both lines and typing the LIST command. The Angle in XY Plane will show the measurement for each segment in bearings, not azimuths. I simply find the difference between the Angles in XY Planes for both lines to determine the angle. I have a few concerns with this method.

1. How do you add subtract bearings measured in degrees, minutes, and seconds? For example, N 76d3'18" W and N 13d56'42"E? I "think" there are websites that can do this? Can this be done directly in AutoCAD through QuickCalc or some other tool?

2. Lines, but not polylines, have Angles in XY Planes in the LIST command. Is this because AutoCAD assumes that polylines will be composed of more than one segment (and each segment with a possible different angle)? Is there anyway to measure the angle of a single one-segment polyline?

Is there a DIFFERENT way between the two methods I just described to measure the angle between two lines (and two polylines) in AutoCAD?

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i know DIMANGULAR command will let me draw a dimension to display the angle between two lines, but is there a way for my commandbar to show me what the angle is rather than draw a dimension?

I often want to simply know the angle but not display it in the drawing, and it'd be good if there was a command/lisp which showed me in the command line area, or perhaps a pop up window, similar to what the TLEN lisp does here: URL....

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Jun 23, 2012

I am drawing a diagram to describe a mathematical word problem. Since it is easier to visualize with a drawing, I want to draw it using the given dimensions. But angles used in the diagram are unknown and are not needed for the answer to be calculated, so the only way to draw this freehand is to guess at the angle resulting in the correct distances to be off.

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Can AutoCAD calculate the angle needed to place a line of a given length between two parallel lines that are a distance apart less than the length of the line to place between them, having the endpoints of this line touching the parallel lines, fitting exactly?

For the word problem, the distance between the two parallel lines is what needs to be solved and the math is quite invloved, having to find the roots or solution of a quartic equation. (I have the solution figured out to be 26.03287754 feet)

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