AutoCAD Civil 3D :: Single Transition Between Two Reverse Curve
Jul 29, 2012I want to add a single transition curve between two reverse curve in Civil3D.
I am using Civil3d2012.
I want to add a single transition curve between two reverse curve in Civil3D.
I am using Civil3d2012.
I need to put a reverse curve on an alignment. I have tried using two free curve fillets,(between two entities, radius). the first curve was fine, but it would not allow the second curve. I also tried using a floating curve ( from entity radius through point) first, but it did not work.
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Dell Studio XPS 9100
Intel Core i7 CPU 930 @ 2.8GHz
12GB Ram
64 bit
C3D 2012 SP3.0
I have edited the "GeneralLegalPhrasings.xml" file used for the parcel report "General_Legal_Description_for_Parcels".
Two issues: 1. it will not label a reverse curve properly....it shows them all as "compound curves". 2. A curve to curve is always shown as "NonTangent".
I've attached the .xml file (I only edited the imperial parcels - the second large group of <Metes>).
Quite simply, these two "types" below have the words "reverse curve" and tangent or non-tangent accordingly in the output phrase, but it only creates non-tangent compound reports.
Curve to TangentReverseCurve
Curve to NonTangentReverseCurve
This is the report from the parcel in the attached dwg file (notice the "curve to the left" -> "curve to the right" labelled as compound, and all non-tangent curve to curve):
From the POINT OF BEGINNING; Thence, North 90° 00' 00" West, 129.16 feet to a point for corner;
Thence, North 00° 00' 00" East, 100.00 feet to a point for corner, the beginning of a curve; tangent
Thence, 61.46 feet along the arc of a ____ curve to the right, having a radius of 39.13 feet, a central angle of 90° 00' 00", and a chord which bears North 45° 00' 00" East, 55.34 feet, to a point for corner, the beginning of a compound curve; non-tangent
Thence, 47.09 feet along the arc of a ____ curve to the left, having a radius of 29.98 feet, a central angle of 90° 00' 00", and a chord which bears North 45° 00' 00" East, 42.40 feet, to a point for corner, the beginning of a compound curve; non-tangent
Thence, 94.33 feet along the arc of a ____ curve to the right, having a radius of 30.03 feet, a central angle of 180° 00' 00", and a chord which bears North 90° 00' 00" East, 60.05 feet, to a point for corner;
Thence South 00° 00' 00" West, 169.11 feet to the POINT OF BEGINNING and containing 0.483 acres of land.
Civil 3D 2011
Windows 7 x64
How to generate reverse curve details from the alignment
i.e. i want to generate
delta
length of reverse curve
transition length
deflection angle (delta) of transition curve
shift
etc ........
i want them to generate in the plan.
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A couple things I did different from the video lectures...
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Inventor 2011 / Windows 7 Pro SP1 64bit
Dell Precision T3600
Intel Xeon E5-1607 @ 3.00GHz
AMD FirePro V4900
20 GB Ram
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Here is a picture of the Corridor Properties:
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