GIMP :: Script-fu - Best Way To Use Drawable-transform-rotate?

I'm new here, as well as to script-fu, although I've looked into Scheme and Lisp and know how to program. I'm using Gimp 2.6.12 (the latest version on Linux - Ubuntu 12.04.2)

So, an overview of what I'm trying to do: create a simple clock face (black) with 12 solid white rectangles at the hour marks.

I have a single layer, (black background, white foreground colours), I select a circle, invert the selection and bucket fill.

Then I select a rectangle, fill it, rotate the layer (which cuts out the rectangle, creates a floating selection with it, and rotates that) anchor the flt-sel (and then repeat 12 times).

> (gimp-rect-select image 570 396 25 8 2 0 0) ; select rectangle
(#t)
> (gimp-bucket-fill layer 0 0 100 0 0 0 0) ; fills the selection (stays selected)
(#t)
> (gimp-drawable-transform-rotate layer (/ PI 2) 0 400 400 0 2 0 3 0) ; creates a flt-sel, but returns layer instead of the flt-sel(!?) ...
(4) ; (also deactivates selection)
> (set! fs (car (gimp-image-get-floating-sel image))) ; ... so have to get the flt-sel explicitly
26
> (gimp-floating-sel-anchor fs)
(#t)

This kinda works, but doesn't feel like the optimal way to do it . What I was expecting to do is something like copying the selection, 12 x (rotate and add), bucket-fill.