I am almost sure this is not possible in AI but I will ask it anyway:
is it possible to assign value of parameter as a result of non linear equation?
for example I would need parameter x to meet the equation
cos^2x+Ax+C=0
where A and C can be other fixed parameters.
how can i access the value in this column using vba?
View 1 Replies View RelatedCan i make an Equation Curve such that it is dependent on a parameter from my Parameters list?
View 1 Replies View RelatedIs there any way in which the text of a text parameter, which is in the equation column, can be replicated into the nominal value column in the parameters table? I want to reference the value of the parameter in Custom iProperties but it always comes up as blank because it has no value.
I need it to update automatically, e.g not entering the value manually.
Trying to display a field of a linear parameter.
Keep getting the dreaded "######" as a result.
Tried regen, fieldeval to 31, some battman prompt etc etc
First i have to mention i am using a mac.
We are supposed to make a block (window for house) and in the windows version, apparently when entering BLOCK EDITOR - a tool palette comes up where you are able to choose "Linear Parameter" and then an arrow comes up where you can pull the arrows to each side.
MY PROBLEM: is that when i enter block editor this tool palette doesn't show, and i cant find where this linear parameter is.
If there was a way to have multiple stretch boxes when selecting one linear parameter.
I am currently working on 2D isometric drawings. I have lined up my views horizontally, so one stretch block is sufficient for stretching things vertically (I just drag the box over all my views), but I cannot find a way to efficiently stretch several views horizontally.
I was hoping that a solution to this will allow me to either select one grip and move at most 4 views horizontally, or just enter ONE value in the quick properties window.
The only idea I can think of now is to just make 4 linear dimensions, 4 grips, and have 4 quick properties inputs .
I am trying to be able to have my outreach arm stretch horizontally and on angles of 5 / 10 / 15 degrees from the pole. I have been able to make the polar stretch for this and it works fine though what i am trying to do is have the luminaire height also stretch and move when the size of the outreach changes (i can make the linear dimension work the way i want though not the luminaire parameter) as when you add the paremter into the stretch action is only moves the top and leaves the bottom at the same location which is not giving me the correct height.
The block itself is alot more complicated then this I have stripped most of the parameters out to make it less confusing but the end result would allow the user to input the outreach angle, outreach length and luminaire height. I have attached drawing for your reference.
We use electircal elements in AutoCAD dwgs that have labels to indicate the status of the element by phase. For instance on a floor plan we might have elctrical outlets that are existing (E), new (N), demo (D), etc. How does one do this efficietnly in REVIT? Is there a way to assign a paramter to grab the phase of the object and then adjust a label accordingly? This would be ideal because over time the element s might move from one phase to another such as from new to existing.
View 2 Replies View RelatedI have user parameters that are no longer needed and are not being used anywhere. They each takes 4-5 seconds to delete, prior to 2012 this would happen instantly.
IV2014 SP1 64bit
Dell Precision T7500, Geforce GTX 480, DirectX11 306.97
SpaceExplorer 4.04, 3DxWare 3.12.2
Twin Intel Xeon E5506 2.13GHz, 12GB RAM, Win7 Pro SP1 64bit
I need to convert a model parameter to a reference parameter thru the API.
I saw this item discussed in the group before, but I cant find the thread.
I got a deadline for my project, but I got a big problem:
"I cannot set the "parameter" for the End Value in Parameter Animate dialog"
For easy understand, let's see a example:
1. I got a part which has two parameters named: "A" and "MaxA"
2. I animate Favorited parameter A.
3. The End Value is MaxA_ (Everything is ok)
4. I finish Studio environment, then I change parameter MaxA_ from 200 mm to 400 mm
5. I turn back to Studio environment, the End Value now is "200 mm" (I want this will be MaxA_, so I can animate the flexible parameter).
show me how to keep the end value will be "MaxA_" after I change parameter?
I'm just starting out with learning equation curves in Inventor.How can I get this curve
r(t)= ti + 4cos tj +9sin tk; where t is greater than or equal to 0
how to get this VBA as an equation curve
I need to make a model of saddle surface. The surface is given by equation z = y^2 - x^2, and I must have some thickness - It will be printed on 3D printer.
I have Inventor 2014 and I dont see possibility of making the surface directly in Inventor. Is there any trick for that?
I'm afraid I cannot use solution as stated here Equation-driven surface , because saddle surface looks like this hyperbolic paraboloid .
I tried this solution: I made 3D surface in Matlab, exported it in .stl and opened in Inventor - but this only makes the surface with no thickness. Functions extrude, loft require 2D sketch.
Can an equation be used to calculate equal distances when using the rectangular pattern.Regarding the attached .ipt file i would like to place 25 holes in the X direction with equal gap size between each hole.Also how to calculate the number of holes in the Y direction again with equal distance between each hole.I have not done this before with equations but was thinking that i would need to use the Length x Width in the equation.Do i need to add figures into the Parameters box also?
The attached file with the Hole feature the sketch is not constrained for the purpose of using an equation so i know how far from the start of the part to get equal distances between each hole to the end of the part .
I need to put the following into equation form to plug into a User Parameter:
if d91 falls in the range of 4" to 11"
then d92 = d91 + 2"
else d92 = 7.5"
Windows 7 Pro, SP1
Inventor 2012 SP1
Due to the nature of our business, I am not permitted to attach any files showing models or .idw environments of any actual work-related components.
I need to put in the polar equation r=e^theta. Is this even possible in autodesk? How can I do it? Should I spline through points instead?
View 4 Replies View RelatedWe have some equations in our templates which i have modified with iLogic. Once the rule is run it only shows the value and not the equation. ie i want it to show Thickness*2 instead of just '12'. The ilogic will say something like InnerRad = Thickness * 2 Is there a way to make it show the equation rather than the value? While i know whats going and can see the driven link in the parameters the planned change to 2012 could take some getting used to for users.
View 9 Replies View RelatedI was trying to use ipart to create some parts and place the relevant dimensions in the table format in the idw file. However, the equation for the dimensions appeared and I like to have it as numeric. Also, the feature present or absent is preferred to be called "Yes" and "No" instead of "Computed" and "Suppress" respectively.
View 1 Replies View RelatedI have an asssembly stack and I have a known bending moment at a given place (ie the datum). I want then to create a drawing of this stack up and show the bending moments at known locations beside the relative dimension.
Now I can do this manually no problem...but I would like this drawing to update automatically. ie the stack up height(s) change and i want the bending moment figure to update accordingly.l
Is there a way to do this with drawing dimensions? ie dimensions created in drawing mode?
I'm trying to use the equation curve to draw a super ellipse.The formula I'm trying to translate for inventor is the following.I'm guessing this should be possible using the abs() for the first section and an IF() statement for the second. The problem is Iäm not even getting the abs() to work at all. How to translate this formula?
View 1 Replies View RelatedTrying to do something as simple as y=x^3 (Explicit Mode). Set xmin = 10, xmax = 20 then tried y(x) = :
1in *(x^3) -- no good
(x^3)/1 in -- no good
(x/1 in)^3 -- no good
Error is that "Equation y(x) contains errors. Expected units are length".
The point here is: Why should typing in such a simple equation as y=x^3 be so difficult??? Can't even do (x*x*x)/1 in & make it work.
I have a small assembly with the parts. I'm doing an array (pattern) of one of the parts and I tried to do two things without success:
1. Tried to link one of the parts to the assembly itself with the equation tool ,but the software doesn't let me do it and says "...was rejected since it causes a cyclic dependency" - so what?:-) I know and need to do it!
2. After rejected the first choice, I tried to "project geometry" some stuff of the pattern I created in order to try and and make my connection in this way, but then I got a similar rejection: : problem encountered when doing cross part projection"...probably it's because it's from a pattern I'm creating from the part I'm doing this sketch inside?
What Can I do in order to bypass these remarks and make it somehow? Most important, Why can't one "tie" something from a part to its own assembly in which it's located???
Inventor 2012 Pro.
I7 workstation
What are the parameters for a parametric 3D Equation Curve to create a path for a coil similar to that in the attached image?
Or alternatively tell me how I can produce the coil in some other way!
what the 2D or 3D equation curve for a parabolic spiral, otherwise known as a Fermat's spiral would be? I have found this info but do not know how to apply it:
Fermat equation
Therefore in terms of the affine plane its equation is
The Fermat curve is non-singular and has genus
I have also found this: $r^{2}=a^{2} heta $
Please see image attached.
I am trying to publish to the CC a guide rail. The vendor of the rail gives me the option of entering the desired length of the rail. After that he gives me the option to choose between the length that I entered and a shorter and longer standard length witch can be delivered faster.
I want to do the same thing with my published part, but I cannot make a key parameter to change depending on the entered custom parameter. I want the user to make the next steps when inserting from the CC: 1- select the size of the rail; 2-select the type of the rail; 3- enter the desired length of the rail; 4- choose between the desired length and the 2 recommended lengths (I need these 3 lengths to be shown)
Is this possible?
I am trying to create a coil which from above, retains equal and thus parallel pitches whilst at the same time adheres to a semi-circular form in the cross section. You can see from the images attached that the first two revolutions are larger than the semi-circle outline.
These are the values I have used:
Cylindrical
r (t): 134.56924424045517662353735770102mm * t * 0.5
q(t): 1 deg * 360 ul * 3.0 ul * t
z(t): 10 mm * 6 ul * 0.5 ul * t * (1.5 * t) * t
tmin: 0 ul
tmax: 0.916 ul
You can create a variable pitch helix by using the Equation Curve feature introduced in Inventor 2013.
Create a new 3D Sketch. Start the Equation Curve command.
Here are equations that I use to create helical curves. Many other variations exist.
Cartesian coordinates:
x(t) = radius * sin(360 * num_turns * t)
y(t) = radius * cos(360 * num_turns * t)
z(t) = height * t
[Code]....
When you sweep a profile along a helical path, use the plane normal sweep (instead of perpendicular sweep) to orient profiles suitable for coil or spring. In the example below, the sweep path is a constant radius, variable pitch helix.
I would like to create an equation driven curve with inventor. I have no problems plotting the function in a plotter, however, inventor won't accept my equation. It gives me the error message, saying: "The equation contains unit errors". I'm using the explicit equations.That's the bare equation:
"y=sqr(2)*16.5/2/sqr(pi)*sqr(arccos(1-2*x/50)-(sin(2*arccos(1-2*x/50))/2))"
I modified it, inserting variables which I defined also in inventor, leading to this:
"sqrt(2)*height/2/sqrt(PI)*sqrt(acos(1-2*t/length)-sin(2*acos(1-2*t/length))/2))"
But both equations are not accepted by inventor due to unit errors. In this design, I'm using the metric system, millimeters, so I don't understand why and how I have to redefine this for the equation in order to get it working.
Is there a way to graph a curve using an equation over a closed interval in Inventor 2012? I know I can draw a spline through points that are solutions of my equation, but this does not guarantee that the curve is the graph of my equation.
View 2 Replies View Relatedcreate an ellipsoid with a hyperbolic funnel on the end.
How can I join an equation curve to an ellipse to create revolved ellipsoid shape? I also have alias and fusion if these are needed.
