create an ellipsoid with a hyperbolic funnel on the end.
How can I join an equation curve to an ellipse to create revolved ellipsoid shape? I also have alias and fusion if these are needed.
I'm trying to use the equation curve to draw a super ellipse.The formula I'm trying to translate for inventor is the following.I'm guessing this should be possible using the abs() for the first section and an IF() statement for the second. The problem is Iäm not even getting the abs() to work at all. How to translate this formula?
View 1 Replies View RelatedI want to draw hyperbola curve whose equation is x^2/a^2 - y^2/b^2=1. May I use equation curve tool to make the above hyperbola.
I have also made a hyperbola curve of aforesaid equation through conventional method on mathematical ground in the past.
I'm just starting out with learning equation curves in Inventor.How can I get this curve
r(t)= ti + 4cos tj +9sin tk; where t is greater than or equal to 0
how to get this VBA as an equation curve
Trying to do something as simple as y=x^3 (Explicit Mode). Set xmin = 10, xmax = 20 then tried y(x) = :
1in *(x^3) -- no good
(x^3)/1 in -- no good
(x/1 in)^3 -- no good
Error is that "Equation y(x) contains errors. Expected units are length".
The point here is: Why should typing in such a simple equation as y=x^3 be so difficult??? Can't even do (x*x*x)/1 in & make it work.
Can i make an Equation Curve such that it is dependent on a parameter from my Parameters list?
View 1 Replies View RelatedWhat are the parameters for a parametric 3D Equation Curve to create a path for a coil similar to that in the attached image?
Or alternatively tell me how I can produce the coil in some other way!
what the 2D or 3D equation curve for a parabolic spiral, otherwise known as a Fermat's spiral would be? I have found this info but do not know how to apply it:
Fermat equation
Therefore in terms of the affine plane its equation is
The Fermat curve is non-singular and has genus
I have also found this: $r^{2}=a^{2} heta $
Please see image attached.
I am trying to create a coil which from above, retains equal and thus parallel pitches whilst at the same time adheres to a semi-circular form in the cross section. You can see from the images attached that the first two revolutions are larger than the semi-circle outline.
These are the values I have used:
Cylindrical
r (t): 134.56924424045517662353735770102mm * t * 0.5
q(t): 1 deg * 360 ul * 3.0 ul * t
z(t): 10 mm * 6 ul * 0.5 ul * t * (1.5 * t) * t
tmin: 0 ul
tmax: 0.916 ul
You can create a variable pitch helix by using the Equation Curve feature introduced in Inventor 2013.
Create a new 3D Sketch. Start the Equation Curve command.
Here are equations that I use to create helical curves. Many other variations exist.
Cartesian coordinates:
x(t) = radius * sin(360 * num_turns * t)
y(t) = radius * cos(360 * num_turns * t)
z(t) = height * t
[Code]....
When you sweep a profile along a helical path, use the plane normal sweep (instead of perpendicular sweep) to orient profiles suitable for coil or spring. In the example below, the sweep path is a constant radius, variable pitch helix.
I would like to create an equation driven curve with inventor. I have no problems plotting the function in a plotter, however, inventor won't accept my equation. It gives me the error message, saying: "The equation contains unit errors". I'm using the explicit equations.That's the bare equation:
"y=sqr(2)*16.5/2/sqr(pi)*sqr(arccos(1-2*x/50)-(sin(2*arccos(1-2*x/50))/2))"
I modified it, inserting variables which I defined also in inventor, leading to this:
"sqrt(2)*height/2/sqrt(PI)*sqrt(acos(1-2*t/length)-sin(2*acos(1-2*t/length))/2))"
But both equations are not accepted by inventor due to unit errors. In this design, I'm using the metric system, millimeters, so I don't understand why and how I have to redefine this for the equation in order to get it working.
Is there a way to graph a curve using an equation over a closed interval in Inventor 2012? I know I can draw a spline through points that are solutions of my equation, but this does not guarantee that the curve is the graph of my equation.
View 2 Replies View RelatedOkay so is there anyway to enter the whole equation of an ellipse into autocad and it will map it? ex x^2/a^2+y^2/b^2+z^2/c^2=1 with different values for x y z a b c. I want to generate different ellipses and then loft them together?I just want one the starts with the basics and goes all the way to the move advance stuff.
View 3 Replies View RelatedCan I create a specific curve in latest released version of AutoCAD by an equation?
If yes, what version of AutoCAD is it, and also how to enter the equation?
I am trying to write a script to draw geometric figures in Illustrator.I want to achieve this by writing an equation into the ESTK, for example x^2 + y^2 =100. This should generate a circle with a radius of 10 units.
View 1 Replies View RelatedSo I have a friend who creates business cards and logo's with elipses and she's running into a problem. She has currently got the trial version of Illustrator CC and while she can create the elipses just fine, she can't seem to get the text to follow the curve.
She does have the right tool correct? Illustrator can do what she wants it to do correct? If so, is it an issue of usage ignorance or could it be that the trial simply doesn't have this feature?I recommended the Illustrator as the right tool but I want to make sure it will do what she's wanting to do.
How to draw hyperbolic paraboloid ind 3D?
View 9 Replies View RelatedI need to make a model of saddle surface. The surface is given by equation z = y^2 - x^2, and I must have some thickness - It will be printed on 3D printer.
I have Inventor 2014 and I dont see possibility of making the surface directly in Inventor. Is there any trick for that?
I'm afraid I cannot use solution as stated here Equation-driven surface , because saddle surface looks like this hyperbolic paraboloid .
I tried this solution: I made 3D surface in Matlab, exported it in .stl and opened in Inventor - but this only makes the surface with no thickness. Functions extrude, loft require 2D sketch.
Can an equation be used to calculate equal distances when using the rectangular pattern.Regarding the attached .ipt file i would like to place 25 holes in the X direction with equal gap size between each hole.Also how to calculate the number of holes in the Y direction again with equal distance between each hole.I have not done this before with equations but was thinking that i would need to use the Length x Width in the equation.Do i need to add figures into the Parameters box also?
The attached file with the Hole feature the sketch is not constrained for the purpose of using an equation so i know how far from the start of the part to get equal distances between each hole to the end of the part .
I need to put the following into equation form to plug into a User Parameter:
if d91 falls in the range of 4" to 11"
then d92 = d91 + 2"
else d92 = 7.5"
Windows 7 Pro, SP1
Inventor 2012 SP1
Due to the nature of our business, I am not permitted to attach any files showing models or .idw environments of any actual work-related components.
how can i access the value in this column using vba?
View 1 Replies View RelatedI need to put in the polar equation r=e^theta. Is this even possible in autodesk? How can I do it? Should I spline through points instead?
View 4 Replies View RelatedWe have some equations in our templates which i have modified with iLogic. Once the rule is run it only shows the value and not the equation. ie i want it to show Thickness*2 instead of just '12'. The ilogic will say something like InnerRad = Thickness * 2 Is there a way to make it show the equation rather than the value? While i know whats going and can see the driven link in the parameters the planned change to 2012 could take some getting used to for users.
View 9 Replies View RelatedI was trying to use ipart to create some parts and place the relevant dimensions in the table format in the idw file. However, the equation for the dimensions appeared and I like to have it as numeric. Also, the feature present or absent is preferred to be called "Yes" and "No" instead of "Computed" and "Suppress" respectively.
View 1 Replies View RelatedI have an asssembly stack and I have a known bending moment at a given place (ie the datum). I want then to create a drawing of this stack up and show the bending moments at known locations beside the relative dimension.
Now I can do this manually no problem...but I would like this drawing to update automatically. ie the stack up height(s) change and i want the bending moment figure to update accordingly.l
Is there a way to do this with drawing dimensions? ie dimensions created in drawing mode?
I have a small assembly with the parts. I'm doing an array (pattern) of one of the parts and I tried to do two things without success:
1. Tried to link one of the parts to the assembly itself with the equation tool ,but the software doesn't let me do it and says "...was rejected since it causes a cyclic dependency" - so what?:-) I know and need to do it!
2. After rejected the first choice, I tried to "project geometry" some stuff of the pattern I created in order to try and and make my connection in this way, but then I got a similar rejection: : problem encountered when doing cross part projection"...probably it's because it's from a pattern I'm creating from the part I'm doing this sketch inside?
What Can I do in order to bypass these remarks and make it somehow? Most important, Why can't one "tie" something from a part to its own assembly in which it's located???
Inventor 2012 Pro.
I7 workstation
Is there any way in which the text of a text parameter, which is in the equation column, can be replicated into the nominal value column in the parameters table? I want to reference the value of the parameter in Custom iProperties but it always comes up as blank because it has no value.
I need it to update automatically, e.g not entering the value manually.
I am almost sure this is not possible in AI but I will ask it anyway:
is it possible to assign value of parameter as a result of non linear equation?
for example I would need parameter x to meet the equation
cos^2x+Ax+C=0
where A and C can be other fixed parameters.
I have an iPart that I have created parameters to perform some basic calcs so the values will show up on every member. The parameters are correct for the different member so it appears to be working correctly on the model side. For example I have a parameter called 'CutLength' that performs simple math functions. But when I make the table on the drawing and I include this parameter, I see the formula in the table instead of the value. Is there a way I can have it display the value instead of the equation?
View 2 Replies View RelatedI'm having difficulty with a sheet metal part creating a flat pattern for it. The shape is an ellipse with the dimensions shown in the second picture. When I attempt to create a flat pattern it just shows the side of the part. The sheet metal defaults are correct for the part and it was ripped to created a base point for the pattern. I need to create a DXF for manufacture. I would just use the flat pattern it gives me and mirror it twice to create a pattern but it doesn't factor in the radius of the part. How to create a correct flat pattern for this item?
View 5 Replies View RelatedI'm trying to dimension an ellipse in the Inventor Drawing Feature. I've attached the .idw files. (the .ipt is too large)I am aware that the ellipse doesn't have a constant radius and was wondering what is accepted practice for these dimensions?
I need to first dimension the external elliptical shape (which I'm struggling at), might just add a note.
Secondly I'm trying to dimension the mesh part, its not centrally align to the part and since I can't put a center mark on I'm not sure how I should dimension this...