AutoCAD Inventor :: Get Dimension To Be Square Root Of 32?
Apr 25, 2012
I want a dimension to be the square root of 32, so I entered:
Sort(32 LU)
Now, the square root of 32=5.656854...
But the dimension I get is 2.227...
So, I try to play with the numbers a little to decipher what Inventor is doing. If I enter:
Sort(32 LU)*2
I get 11.314...
2.227*2 does not equal 11.314
However,
(√32)*2=11.313708...
This is the first time I have used equations that are more complicated than basic math.
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Oct 14, 2013
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