I cannot make a plane parallel to a surface and through a sketch point.
I can't also select the sketch point or line in order to make an axis. the sketch point, line from the sketch or anything from a sketch isn't selectable.
I`m using Inventor 2012.When i select a new sketch from the New file drop down selection box ( new sketch picture) the XY plane is a different view to when i select a new sketch from the Part selection box (new sketch 1).
How can i make a default work plane when opening a new sketch?I would like to have the work plane identical to the new sketch picture when ever i open a new sketch file
I was trying to query some sketch points data from a profile Path using code as below. However the program stopped without telling the reason.
Code below:
i = 0;
foreach (ProfileEntity oSourceProfileEntity in oProfilePath) { switch (oProfilePath[i].SketchEntity.Type) { case ObjectTypeEnum.kSketchArcObject: { SketchArc srcSkArc = default(SketchArc); srcSkArc = (SketchArc) oSourceProfileEntity.SketchEntity; // error points[i] = srcSkArc.StartSketchPoint.Geometry; break; } default: { SketchLine srcSkLine = default(SketchLine); srcSkLine =(SketchLine) oProfilePath[i].SketchEntity; // error points[i] = srcSkLine.StartSketchPoint.Geometry; break; } } i++; }
When I pick the XZ plane to create a new sketch, then Look At it, the red origin indicator is pointing left, meaning I'm on the back side. How did I get over on the front side. Something with flip axis or something like that?
View 9 Replies View RelatedI have a one rectangular block(Control cabinet) it consists of around 100 sub rectangular blocks here problem is in my part user wants few blocks in different dimensions and different positions some time. So I created one sketch in my sketch plane then user wants more features on rectangular block then I want automatically copy and paste on same plane same sketch and same time automatically asking for dimensions(positional, length and width).
View 3 Replies View RelatedI am jammed in this matter...I have my 3d sketch and i would like to control the angle betewwen the two planes with
the dimension of the 3d sketch. I am at the level that i can change angle between planes.
I use AddByNormalToCurve method to create a work plane in a sketch 3D. Is it possible to make new workplane object to be consumed by the parent Sketch3D (Workplane.Consumed = True) as it is possible in UI in Edit mode ?
My sample code in IV 2008:
Public Sub WorkPlane_Test()
'reference to the transient geometry
Dim oTG As TransientGeometry
Set oTG = ThisApplication.TransientGeometry
'reference to the component definition
[code]........
When I tried to make a sketch plane on one of the surfaces of the revolved feature, it only had the option to edit the original sketch or the feature even though the sketch that I'm trying to create is on a different plane. There is one surface that allows me to add a sketch plane.
View 5 Replies View RelatedHow does one constrain a sketched line in the sketcher to a datum plane?
View 5 Replies View RelatedI added another extrusion profile to my structural shapes library, using the same method as the others a few years ago. It works, but the new extrusion now shows up with its profile sketch, start and end planes, and driven dimension visible. The old stuff doesn't (like I would expect). I have all planes in the published part turned off, not marked for export, etc., just like in the old ones. How do I turn this off? Inventor 2012 SP2.
When I open the extrusion separately, the work features to not display. But, the it's also shown as the "default" color not as material. Why does it default to "default" not "as material" like everything else?
When ever I start a new sketch in the xz plane (viewing from top down) my sketch rotates 180 degrees. Not a huge deal to rotate it back, but not everything I create is symetrical and when I go to draw the part, I want a certain ISO view to be default. I know you can insert/obtain any view into the drawing but is there an option to stop this rotation or maybe I am not setting up something correctly.
Using Inventor Pro 2012
Inventor Professional 2014-Update 2 - AutoCAD Electrical 2014
Win7-x64 | ASUS P8Z77-V | i7 3770 -3.4 GHz | 32GB RAM |
240GB SSD | nVidia GTX 670 4GB - 320.49
Here I attached my model view it's just for reference here iam using rectangular pattern and simple ilogic code .Using rectangular pattern we will get all same sizes of boxes but i want to change different different sizes and positions. my idea is without using pattern just draw one rectangular through parameter. Select no. of compartments automatically copy and paste that rectangular in same sketch plane and ask sizes and positions dimensions.
It's possible through ilogic?
In my panel bar options are:
Hight of panel- Hight of panel
width1- Width of panel
Depth1-Depth of panel
com1- no.of Compartments
hIN- No.of Hinges
I would like to be able to offset a 3D Sketch in a direction normal to a plane. In the attached image, I have drawn in an orange color the direction I would like the 3DSketch to offset.The white line is where the new sketch would be.
The yellow surface is the 3dsketch extend to a plane
There might be some tools in Inventor that will do what I am trying, but I have not found it yet. I have tried extend surface, but that will not take it the direction I want.
Working on setting up 2013 for our department. By default we use the application option - Part Tab - of creating a sketch on the x-z plane upon new part creation. Now this actually works, problem is you can't draw on it, or you can't see what you are drawing. If you exit out of the sketch and start a new one then it works. I have found that if you switch the setting to the y-z plane is does the same thing. Switching it to no new sketch or the x-y plane and it works fine. Tying to determine if it's actually a bug in inventor or if it's just something with what I am doing or our template files.
View 5 Replies View RelatedIn the programming I found an example to place an ifeature on a face.I've modified it to place it on a face without selectset but with features. faces. item(1)
how to place it on that face with a vertex from that face or a workpoint that lies on that face.I've tried to adapt other code on this forum but can't find it.
I very often find that I would like to create a work plane defined by an axis and a point such that the plane is spanned by the point and the axis. But the only possible way seems to be to create a plane through the point and perpendicular to the axis.
View 9 Replies View RelatedI use vb.net draw a cube frame (just point and add edge to link points) in 3dsketch. But at the corner, I got only one edge, the others are filled that is a arc is inserted between the 2nd & 3rd edge to the corner point. There is no second edge is extended to that point.
Just wondering why I got the result. There is no fillet command in my code.
I want to concide two points of two different lines.These two lines have been created in two different workplanes with 2D sketch.
View 7 Replies View RelatedI'm trying to contrain the end points of 2 lines using iLogic. I know the end points but I cannot get the values into the SketchPoint object. The real odd thing is I can create the lines no problem. I tried it 2 different ways shown below. The first way gives me this error..."Object reference not set to an instance of an object.". The second says "Unable to cast COM object.."
Dim oTG As TransientGeometry
oTG = ThisApplication.TransientGeometry
Dim EntityEndPt As SketchPoint
EndPtX = 0 * 2.54
EndPtY = 3 * 2.54
‘Code Fails Here!
EntityStartPt.Geometry.X = EndPtX
I just want to know that how can I get the center point from a Sketch Object ?
View 1 Replies View RelatedHow would one add a sketch-point to a midpoint of an arc? For a SketchLine its easy...
oSketch.GeometricConstraints.AddMidpoint oSketchPoint, oSketchLine
However, I can't see how to do the same operation to find the midpoint of a SketchArc. The interface of course has a selection filter for this so I assume the API can do the same?
The screen shot below shows three coincident constraints and a projection icon on the origin.
looks like a projection icon - what does it mean?
I want to delete the three coincident constraints. But when I delete the coincident constraints there is no Sketch origin center point (the sketch origin center point is a square-yellow dot at the x-y intersection). How to delete or move the three coincident constraints with out deleting the sketch origin center point?
I have this assembly shown in the pic. below. I'm trying to create a point or axis in the blue corner points (to attaches something later on) but it just won't let me choose it for some reason. I know that it's possible to to do that (almost sure I already done this trivial thing in inventor.)
Any reason it's not letting me choose the sketch points/line to in order to create points or axis(s)?
Inventor 2012 Pro.
I7 workstation
how do I retrieve the centre point in my design axis in Inventor, when I create a new sketch, like the point at x0:y0:z0
View 2 Replies View RelatedIt goes f.e. like this:
I draw a line (no constrains) and I can move it by grabing an end or whole line by click&hold mouse button, great.
But after couple minutes of work with part and sketches I can't grab anything. Even on new created sketches and new lines. Click and drag just open rectangle selection. Oh, between these phases there is a phase when 2nd click&hold works...
When I open/create another part it is normall, but this one I must close and open again.
Inventor 2010
Some how I turned off the snap to end point in the sketch mode. where is the dialog box to control snap settings
I would like to use iLogic to find the location of the points of a line, determine if the line is approximately vertical, and apply a vertical constraint if it is vertical.
Here is the code process I envision:
1. Automatically select a straight line.
2. Find the location of its end points.
3. Compare the X-value of the end points to see if they are vertically aligned (or almost so).
4. If they are vertically aligned, apply a vertical constraint.
5. Select next line and repeat.
Is this possible with iLogic? I don't see any way of calling a line's sketch points or finding their location.
I know why you cant loop select and offset the rectangle but surley if you are going to take the time to listen to users and create requested tools, you should do it well?
View 4 Replies View RelatedIn assembly mode, how can I click on two lines in a part sketch and get there intersection point using VBA?
View 3 Replies View RelatedUnfortunately, it's chock full of proprietary customer data, so I can't share the parts or the assembly. But I can pretty well explain what needs to happen, and I've attached a JPG that shows a bit of what I'm doing.
I need to design a bracket to hold an RPM sensor at a certain gap to a spiral bevel gear. I've got a huge assembly model (non-Inventor) from the customer, as well as the model for the sensor. My plan is to start a master IAM, insert the customer assembly, insert the sensor and constrain him, and draw the various hardware I need around the sensor.
So I start by making a work plane that matches the bevel angle and is in a location so the end of my sensor will be flush to that plane. Create a sketch on that plane, then project 2 relevant axes to create the appropriate "origin" from which my location will be based. Place a point on one line, at a certain radial distance and constrain my point.
So now I've got a point and a plane that are where I want my sensing face and my centerline axis to be. What now? I was thinking that I'd create a work axis "normal to plane through a point", but this workflow isn't available in the assembly environment. I can't constrain a solid to a sketch point, so I really don't know what to do at this point in order to put the part where I need it.
I have the German version of Inventor 2014, so some translations may be different.
I want to project a text on a sketch onto a conical surface. The error message is that the chosen surface wasn't tangential to the profile plane. I found no way to rotate the plane.
How do I project my profile onto the conical surface or How do I make the profile plane tangential to the conical surface?